You are watching: Do diagonals bisect each other in a parallelogram
With the being said, i was wondering if within parallel the diagonals bisect the angle which the meet.
For instance, please describe the link, walk $overlineAC$ bisect $angle BAD$ and also $angle DCB$?
If they diagonals do undoubtedly bisect the angle which castle meet, can you please, in layman"s terms, display your proof?
edited might 21 "20 at 10:41
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asked Jun 3 "16 in ~ 16:45
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$egingroup$ Yes however not a common parallelogram, only in a square, rhombus and also kite. $endgroup$
Jun 3 "16 in ~ 17:11
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The diagonals bisect angles just if the sides are all of equal length.
Assume that the diagonals undoubtedly bisect angles.
Then $angle BCE=angle ECD$ in her diagram.
Also $angle ECD=angle EAB$ because $AB | DC$.
So $angle BCE = angle EAB$, hence $ riangle BAC$ is isosceles through $AB=BC$.
Similar arguments likewise prove equality of various other sides, $BC=CD$ and $CD=DA$.
answer Jun 3 "16 at 16:53
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Nope the doesn"t...We can prove it using congruency triangle.U can see that vertically opposite angles are equal.Not the diagonal line bisect angle
answered might 15 "19 in ~ 5:11
HEPIN RAJESHBHAI SAVALIYAHEPIN RAJESHBHAI SAVALIYA
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