You are watching: Do diagonals bisect each other in a parallelogram

With the being said, i was wondering if within parallel the diagonals bisect the angle which the meet.

For instance, please describe the link, walk $overlineAC$ bisect $angle BAD$ and also $angle DCB$?

If they diagonals do undoubtedly bisect the angle which castle meet, can you please, in layman"s terms, display your proof?

Thanks, guys!

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edited might 21 "20 at 10:41

amWhy

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asked Jun 3 "16 in ~ 16:45

RidhwaanRidhwaan

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$endgroup$

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$egingroup$ Yes however not a common parallelogram, only in a square, rhombus and also kite. $endgroup$

–user312097

Jun 3 "16 in ~ 17:11

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## 2 answers 2

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The diagonals bisect angles just if the sides are all of equal length.

Proof -

Assume that the diagonals undoubtedly bisect angles.

Then $angle BCE=angle ECD$ in her diagram.

Also $angle ECD=angle EAB$ because $AB | DC$.

So $angle BCE = angle EAB$, hence $ riangle BAC$ is isosceles through $AB=BC$.

Similar arguments likewise prove equality of various other sides, $BC=CD$ and $CD=DA$.

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answer Jun 3 "16 at 16:53

KalElKalEl

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Nope the doesn"t...We can prove it using congruency triangle.U can see that vertically opposite angles are equal.Not the diagonal line bisect angle

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answered might 15 "19 in ~ 5:11

HEPIN RAJESHBHAI SAVALIYAHEPIN RAJESHBHAI SAVALIYA

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