-2bk2+6bk-2b Final result : -2b • (k2 - 3k + 1) step by step solution : step 1 :Equation at the end of step 1 : ((0 - 2bk2) + 6bk) - 2b step 2 : action 3 :Pulling out prefer terms : 3.1 ...

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-2r4+21r3-54r2 Final result : -r2 • (r - 6) • (2r - 9) action by step solution : step 1 :Equation at the end of step 1 : ((0-(2•(r4)))+(21•(r3)))-(2•33r2) step 2 :Equation at the finish of action 2 ...
-2kb2+6bk-2b Final an outcome : -2b • (kb - 3k + 1) step by action solution : step 1 :Equation at the finish of action 1 : ((0 - 2kb2) + 6kb) - 2b action 2 : action 3 :Pulling out choose terms : 3.1 ...
George C. Might 17, 2015 an alert thatdisplaystyle7=2+5anddisplaystyle10=2 imes5 .So we deserve to factor: displaystylea^2b^2-7ab+10=left(ab ight)^2-7left(ab ight)+10 ...
Alan P. Apr 9, 2015 Factoring by grouping is not a method that is reasonable because that an expression with 3 state (perhaps a 4th term to be intended(?))This expression,displaystyle12a^3+20a^2-48a ...

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9k2+66k+21=0 Two services were uncovered : k = -7 k = -1/3 = -0.333 step by action solution : step 1 :Equation at the finish of step 1 : (32k2 + 66k) + 21 = 0 action 2 : action 3 :Pulling out ...
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left< eginarray l l 2 & 3 \ 5 & 4 endarray ight> left< eginarray l l l 2 & 0 & 3 \ -1 & 1 & 5 endarray ight>

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