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There are instances when that is compelled to recognize the percent the an aspect in a recognized chemical formula. This section will present how to do these calculations.

You are watching: What is the mass percent of sodium in nacl?

There are pertains to that there is too much sodium in our diets. There are plenty of compounds supplied in food products that save sodium. Salt chloride (NaCl, table salt) is the most commonly used link to add salt to foods.

What is the percent sodium in the compound NaCl?Step 1: calculate the gram formula weight for NaCl.

The gram atomic load (GAW) because that Na is 22.99 g / molThe gram atomic weight (GAW for Cl is 35.45 g / molThe gram formula load (GFW) because that NaCl is 58.44 g / mol

Step 2 calculate the % Na in NaCl:From the previous section Determination of chemical Formulas girlfriend should know the calculate is: An Example:A biscuit recipe has salt (NaCl) and baking flour that consists of baking soda (NaHCO3), sodium aluminum sulfate (NaAl(SO4)2 ). I m sorry compound has actually the greatest percent Na? from the calculation above, we know NaCl is 39.34 %.

Percent Na in NaHCO3 :  Percent Na in NaAl(SO4)2  Based ~ above the preceding calculations, NaCl has actually the highest possible % that Na

Knowing the percent ingredient of compound is provided to calculate the grams that an element in a offered mass the the compound(s). An example of this can be shown using a biscuit recipe.

Baking flour is a mixture comprise 30 % baking soda and also 24 % sodium aluminum sulfate.

A biscuit recipe calls because that 3g that NaCl and also 9 g baking powder (NaHCO3 & NaAl(SO4)2)

Since baking flour is 30 % NaHCO3 and also 24 % NaAl(SO4)2 , the first calculation would be to multiply 9 g of baking soda by the percent of each chemical to determine the grams of every chemical, NaHCO3 and also NaAl(SO4)2.

Grams the NaHCO3 = 0.30 x 9 g baking flour = 2.7 g NaHCO3

Grams of NaAl(SO4)2 = 0.24 x 9 g baking flour = 2.16 g NaAl(SO4)2

Grams full from ingredients: = grams indigenous NaCl + grams from NaHCO3 + g native NaAl(SO4)2.

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The calculation is: (using the percents calculation above)

Total grams = (0.3934 x 3 g NaCl ) + (0.2738 g x 2.7 g NaHCO3 ) + ( 0.095 x 2.16 g NaAl(SO4)2 ) = 2.125 g Na

The student will encounter calculations such together these in a constant general chemistry class.