Reformatting the intake :Changes made to her input should not affect the solution: (1): "x3" was changed by "x^3".
You are watching: Which is the factorization of x3 + 8?
Step 1 :
Trying to variable as a difference of Cubes:1.1 Factoring: x3-8 theory : A difference of two perfect cubes, a3-b3 have the right to be factored into(a-b)•(a2+ab+b2)Proof:(a-b)•(a2+ab+b2)=a3+a2b+ab2-ba2-b2a-b3 =a3+(a2b-ba2)+(ab2-b2a)-b3=a3+0+0-b3=a3-b3Check:8is the cube that 2Check: x3 is the cube the x1Factorization is :(x - 2)•(x2 + 2x + 4)Trying to aspect by dividing the middle term
1.2Factoring x2 + 2x + 4 The first term is, x2 its coefficient is 1.The middle term is, +2x that is coefficient is 2.The last term, "the constant", is +4Step-1 : main point the coefficient of the very first term by the constant 1•4=4Step-2 : uncover two components of 4 whose sum equals the coefficient of the center term, i beg your pardon is 2.
Observation : No two such components can be uncovered !! Conclusion : Trinomial can not it is in factored
Final result :(x - 2) • (x2 + 2x + 4)
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